đą Final Quick Summary
 Charge: Q = n à e
 Current: I = Q/t
 Voltage: Energy per unit charge
Resistance: R = V/I
Factors: L â, A â, T â
Resistivity: Ï = R A / L
Heating Effect: H = IÂČRt
Power: P = VI
Units: A, V, Ω, W, kWh
        1. Electric ChargeÂ
- Electric Charge (Q):
- A fundamental property of matter that causes particles to experience electrical forces.
- Two types: Positive and Negative.
- Unit:Â Coulomb (C).
- Behavior:
- Like charges repel each other.
- Unlike charges attract each other.
- Formula: Q=nâ e where  Q= total charge,Â
n= number of electrons (or charged particles),
e= charge of one electron =1.6Ă10â19C
So, if you know how many electrons are transferred, you can calculate the total charge.
2. Electric CurrentÂ
- Definition: Electric current is the rate of flow of electric charge through a conductor. It tells us how fast electrons are moving in a wire or circuit.
- Formula: I=Qt
I = Electric current (in amperes)
Q = Total charge (in coulombs) , t = Time (in seconds)
This formula shows that current increases if more charge flows in less time.
- Unit:Â Ampere (A)Â is the SI unit of current.
- Defined as: 1A=1C1s1A = \frac{1C}{1s}
â If 1 coulomb of charge flows in 1 second, the current is 1 ampere.
- Measurement Tip:
- An ammeter is used to measure current.
- It is always connected in series in the circuit so that the same current flows through it.
3. Electric Circuit
- Definition: An electric circuit is a closed path through which electric current flows. If the path is broken (open), current cannot flow.
- Symbols Used in Circuit Diagrams:Â These are standardized symbols used to represent components:
- Cell â single power source
- Battery â multiple cells connected
- Bulb â load or output device
- Switch â control element (open/closed)
- Wire â conducting path
“These symbols are used in CBSE circuit diagrams to simplify and standardize representation. “
- Direction of Current: Conventional Current: Flows from positive (+) to negative (â) terminal. This is the direction assumed in textbooks and diagrams.Electronic Current: Actual flow of electrons, which move from negative (â) to positive (+). This is the physical reality inside conductors.
đ Page Context
This explanation is part of your step-by-step visual summary for students. It helps them understand:
- What a circuit is
- How to read and draw circuit diagrams
- The difference between assumed current flow and actual electron movement
This is especially useful for CBSE exam questions that ask students to draw or interpret circuits, and for practical understanding in labs.
4. Ohm’s Law Statement:
Ohmâs Law states that the electric current (I) flowing through a conductor is directly proportional to the voltage (V) across it, provided the temperature remains constant.
- Mathematical Form:Â
VâIâV=Iâ R
- VVÂ = Voltage (in volts)
- IIÂ = Current (in amperes)
- RR = Resistance (in ohms, Ω)
- Resistance (R):It is the property of a conductor that opposes the flow of current. Higher resistance â less current for the same voltage.
- Graphical Representation:
- A VâI graph (Voltage vs Current) for a conductor obeying Ohmâs Law is a straight line.
- The slope of the line gives the resistance of the conductor.
đ Page Context
This explanation is part of your step-by-step visual summary for CBSE students. It helps them:
- Understand the relationship between voltage, current, and resistance
- Apply the formula V=IRV = IR in numerical problems
- Interpret graphs in exams and lab experiments
This concept is frequently tested in CBSE exams through numerical questions, graph interpretation, and circuit analysis.
đ§ź CBSE Board Numerical Questions â Ohmâs Law
đč Question 1
A current of 2A flows through a resistor of 5Ω. What is the potential difference across the resistor?
Solution:
V=Iâ R=2â 5=10VV = I \cdot R = 2 \cdot 5 = 10V
Answer: 10 Volts
đč Question 2
If a 12V battery is connected across a resistor and the current is 3A, find the resistance.
Solution:
R=VI=123=4ΩR = \frac{V}{I} = \frac{12}{3} = 4Ω
Answer: 4 Ohms
đč Question 3
A wire has resistance of 10Ω. How much current will flow if 20V is applied?
Solution:
I=VR=2010=2AI = \frac{V}{R} = \frac{20}{10} = 2A
Answer: 2 Ampere
đč Question 4
A bulb draws 0.5A current when connected to a 220V supply. What is its resistance?
Solution:
R=VI=2200.5=440ΩR = \frac{V}{I} = \frac{220}{0.5} = 440Ω
Answer: 440 Ohms
5. Factor affecting Resistance
đ Concept Breakdown: Resistance and Its Influencing Factors:
- Resistance (R): It is the property of a conductor that opposes the flow of electric current. Measured in Ohms (Ω).
đ Factors Affecting Resistance
Factor Effect on Resistance Length (L) Resistance increases with length â RâLR \propto L Area of Cross-section (A) Resistance decreases with area â Râ1AR \propto \frac{1}{A} Temperature Resistance increases with temperature (especially in metals) Nature of Material Insulators & conductors have high and low resistance
- Formula for Resistance
R=Ïâ LA
- RRÂ = Resistance
- Ï\rho = Resistivity of the material (depends on nature of material)
- LLÂ = Length of the conductor
- AAÂ = Area of cross-section
” This formula shows how geometry and material affect resistance.”
đ Page Context
This section is part of your step-by-step visual summary for CBSE students. It helps them:
- Understand how wire dimensions and material choice affect resistance
- Apply the formula in numerical problems
- Interpret graphs and tables in exams and lab experiments

